(iii) ∑F = 0 (Static Equilibrum)

∑Perpendicular forces = 0

W Cos 10° + R = 0

mg Cos 10° = - R

(50 kg X 9.81ms^{-2}) Cos 10° = - R

R = - 483 N (minus sign indicates force is to the left)

(iv) ∑Parallel forces = 0

W Sin 10° + F = 0

mg Sin 10° = - F

-(50 kg X 9.81ms^{-2}) Sin 10° = - F

F = 85.2 N