Let F_{P} be the force on the piston

Radius of piston = 0.25cm

Cross-sectional Area of piston = 1.96 X 10^{-5} m^{2}

Length of handle = 0.25m

Distance of piston from fulcrum = 0.01m

Radius of nozzle = 1mm

Cross-sectional Area of piston = 3.14 X 10^{-6} m^{2}

When the piston is about to move Στ = 0

Clockwise torque + Anticlockwise torque = 0

[-(0.25m X 20N)] + (0.01m X F) = 0

F = 500N

Pressure = Force / Area

Pressure by piston = _{P} / Area

Pressure by piston = 500N /
1.96 X 10^{-5} m^{2}

Pressure by piston = 25.5 MPa.

Pressure is transmitted throughout all part of the fluid

Pressure on nozzle = F_{N} / Area

2.55 X 10^{7 }= F_{N} / 3.14 X 10^{-6} m^{2}

F_{N}= 2.55 X 10^{7 }X 3.14 X 10^{-6} m^{2}

F_{N}= 80.1 N